Question

Ofer 14 puncte + coronita.Este foarte urgent.Cine știe sa rezolve toate subpunctele ofer și mai multe puncte

Answer 1

4) a) x²–4/x²+3x+2 × x²+x/x²–4x+4 = (x+2)(x–2)/x²+x+2x+2 × x(x+1)/(x–2)² =(x+2)(x–2)/x(x+1)+2(x+1) × x(x+1)/(x–2)² =(x+2)(x–2)/(x+2)(x+1) × x(x+1)/(x–2)²(acum putem simplifica ,ce putem ) =x/x–2 =x•(x–2) =x²–2x b) 4x+8/x²+4x+4 • x²–4/4x–8 =4(x+2)/(x+2)²• (x+2)(x–2)/4(x–2) (simplificăm și obținem) =4/4 =1 c) x²+4x/ x²–16 •3x–12/5x+25 =x(x+4)/(x+4)(x–4) • 3(x–4)/5(x+5) =3x/5(x+5) =3x/5x+25 d) x²+2x+1/x²–1 • x²+3x+2/4x+4(facem cu artificiu de calcul) =(x+1)²/(x+1)(x–1) • x²+x+2x+2/4(x+1) =(x+1)²/(x+1)(x–1)• x(x+1)+2(x+1)/4(x+1) =(x+1)²/(x+1)(x–1)• (x+1)(x+2)/4(x+1) =x+2/4 =(x+2)•4 =4x+8 e) 7x+35/x²–25 • x²–7x+10/x²–4x+4 =7(x+5)/(x+5)(x–5)• x²–5x–2x+10/(x–2)² =7(x+5)/(x+5)(x–5) • x(x–5)–2(x–5)/(x–2)² =7(x+5)/(x+5)(x–5) • (x–5)(x–2)/(x–2)² =7/x–2 =7•(x–2)/1 =7(x–2) f) 3x²–12x/x²–8x+16• x²–7x+12/x²–6x+9 =3x(x–4)/(x–4)²• x²–4x–3x+12/(x–3)² =3x(x–4)/(x–4)² • x(x–4)–3(x–4)/(x–3)² =3x(x–4)/(x–4)² • (x-4)(x–3)/(x–3)² =3x/x–3 =3x•x–3/1 =3x(x–3)