Question

Ofer 55 de puncte.Rezolvati cele 2 sisteme:​

Answer 1

Bună!  

  (❁´◡`❁)

a)

$\left \{ {{\frac{x}{y}=\frac{3}{4} } \atop {5x-4y=-3}} \right. => \left \{ {{y=\frac{4x}{3} } \atop {5x-4y=-3}} \right. => 5x-4*\frac{4x}{3} =-3/*3 => 15x-16x=-9 =>$

$=> x=9\\=> y=\frac4*9x}{3} =4*3=> y=12$

(x, y)=(9, 12)

b)

$\left \{ {{2x-y=5} \atop {3x+y=10}} \right.$

_______(+)

5x+ / =15/:5 => x=3

2x-y=5 <=> 2×3-y=5 => -y=5-6 => y=1

(x, y)=(3, 1)