Question

Ofer coroana , de preferat a, c , d :)) Multumesc!

Answer 1

a)

A = propena , CH2=CH-CH3

B = metan, CH4

C = acid acetic, CH3COOH

D = diclorometan, CH2Cl2

c)

165g A impur .................... 100%

m.pur ................................ 80%

= 132 g A

132g         n moli

C3H6   +   H2 --> C3H8

42               1

=> n = 132/42 = 3,14 moli H2 in conditii normale..... dar in conditiile din problema ....??

PV = nRT

=> V = nRT/P

= 3,14x0,082x(273+27)/0,5

= 154,63 L H2

d)

112 cm3 A = 0,123 L A

0,123 L/22,4 = 0,0055 moli A

0,0055 moli

CH2=CH-CH3 + 5[O] --> CO2 + H2O + CH3COOH /x3

   3

  n moli

K2Cr2O7 + 4H2SO4 --> K2SO4 + Cr2(SO4)3 + 4H2O + 3[O] /x5

  5

=> n = 0,0055x5/3 = 0,00917 moli K2Cr2O7

stim ca Cm = niu/Vs => Vs = niu/Cm

= 0,00917/0,5 = 0,0183 L sol K2Cr2O7

sau 18,33 mL sol K2Cr2O7