Question

Ofer multumiri+ coronita
Un biciclist parcurge o distanta de 180 km astfel:
In prima zi parcurge 0,(1) din drum, a doua zi 0,25 din rest . Dupa ce a parcurs toata distanta constata ca 2 supra 13 din distanta parcursa a treia zi este egala cu 2 supra 11 din distanta parcursa in a patra zi.
Ce distanta a parcurs in fiecare zi?

Answer 1

I zi :180•0,(1)=180•1/9=20km_________ a II a zi:(180-I zi)•0,25=(180-20)•25/100=160•1/4=40km____________ a III a zi •2/13=a IV a zi •2/11 |:2_______ aIII a zi/13=a IV a zi/11=>a III a zi=a IV a zi •13/11__________________________ aIII a zi + aIV a zi =180-I zi-a II a zi=180-20-40=120________________________ inlocuim:a IV a zi •13/11+a IV a zi=120__ a IV a zi (13/11+1)=120=>aIVa zi(13+11)/11=120=> a IV azi=120:24/11=120•11/24=55=> aIVa zi=55km.=>aIIIa zi=aIVa zi •13/11=55•13/11=5•13=65km