Question

ordineaoperatiilor si folosirea corecta a parantezelor va rog ajutati.ma 32:(12-4)+8=; (32+40):9-8×1=; 56-20):4+9×9=; (16:4+24):7×8=; 100-(56+4×2-14:2)=; 100-8×6+16:2=; 79+2×7-8×10=; 67-5×9+72:8= .

Answer 1

32:(12-4)+8=
=32:8+8
=4+8
=12

(32+40):9-8*1=
=72:9-8
=8-8
=0

(56-20):4+9*9=
=36:4+81
=9+81
=90

(16:4+24):7*8=
=(4+24):7*8
=28:7*8
=4*8
=32

100-(56+4*2-14:2)=
=100-(56+8-7)
=100-(64-7)
=100-57
=43

100-8*6+16:2=
=100-48+8
=52+8
=60

79+2*7-8*10=
=79+14-80
=93-80
=13

67-5*9+72:8=
=67-45+9
=22+9
=31