Question

Ovidiu, Marian si Alexandra au impreuna 100 nuci.Daca fiecare mananca acelasi numar de nuci, lui Ovidiu ii raman 39 nuci, lui Marian ii raman 25 de nuci, iar Alexandrei ii raman 21 nuci. Cate nuci a avut fiecare?vreau metoda segmentelor

Answer 1

o+m+a=100
o-n=39
m-n=25
a-n=21
o=n+39
m=n+25
a=n+21
|----|+21
|----|+25
|----|+39
21+25+39=85
100-85=15
15:3=5
a=5+21=26
b=5+25=30
c=5+39=44

Answer 2

Ovidiu |_|+39
Marian |_|+25
Alexandru |_|+21
acolada dupa ele si treci 100

39+25+21=85
100-85=15 (3 parti egale)
15:3=5 (valoare unei parti)
5+39=44 (a avut Ovidiu)
5+25=30 (a avut Marian)
5+21=26 (a avut Alexandru)

proba:
44+30+26=100