Question

paranteza patrata6*(4*17-15*4)+78impartit 6 inchidem paranteza patrata +14 impartit (6+72 impartit 9)=

Answer 1

[6×(4×17-15×4)+78:6]+14:(6+72:9)=
[6×(68-60)+13]+14:(6+8)=
(6×8+13)+14:14=
(48+13)+1=
61+1=62

Answer 2

[6×(4×17-15×4)+78:6]+14:(6+72:9)=
=[6×(68-60)+13]+14:(6+8)=
=[6×8+13]+14:14=
=[48+13]+1=
=61+1=
=62