Question

Partea 2 Problema 2 a) va rog frumos :)

Answer 1

Se repetă 0 de același număr de ori la ambii membri ai sumei.

x/33 + x/303 + x/3003 + ...

+ x/3000...003 = 2/11 + 2/101+ 2/1001 + ... + 2/1000...001

(1/3)•(x/11 + x/101 + x/1001 + ...

+ x/1000...001) = 2/11 + 2/101 + 2/1001 + ... + 2/1000...001

(1/3)•(x/2)•(2/11 + 2/101 + 2/1001 + ... + 2/1000...001) = 2/11 + 2/101 + 2/1001 + ... + 2/1000...001

(1/3)•(x/2) = 1

x/6 = 1

x = 6