Question

pct a.b.c.d.
Dau coroniță

Answer 1

b)8/(x-2) E N=>x-2I 8 I+2=> xI 10=> xE{1,10} =>B-{1,10}
c)(3x-2)/(x+4) E N=>x+4I3x-2 I-x=>4I2x-2 O/2=>2Ix-1 I+1=>3Ix =>xE{1,3}=>C{1,3}
d)(4x+3)/(5x-1) E N=>5x-1I4x+3 I-4x=>x-1I3 I+1=>xI4=> xE{1,4} => dE{1,4}