Question

perimentru triunghiului abc = 54 ab/8=ac/6 si bc/2=ac/3 ab , ac , bc = ?

Answer 1

AB+AC+BC=54
AB/8=AC/6⇒AB=8AC/6=4AC/3
BC/2=AC/3⇒BC=2AC/3=
Perimetrul=AC+4AC/3+2AC/3=54⇒9AC/3=54⇒AC=6
AB=8
BC=4

Answer 2

daca AB/8=AC/6=>AB=8AC/6;
din
BC/2=AC/3=>BC=@AC/3;
si
AC=AC;
suma acestora este:
AB+BC+AC=8AC/6+2AC/3
AC/1=54;
aducem la numitor comun:
6*54=8AC+4AC+AC adica:
AC=18 iar
AB=(8*18):6=24 si
 BC=(2*18):3=12;
Proba: 24+12+18=54 (A)