Question

Perimetrul triunghiului ABC=54 ab/2=ac/6 bc/2=ac/3 va rog, raspundeti-mi repede!!!

Answer 1

Răspuns:

Explicație pas cu pas:

ab/2 = ac/6

ab = 2ac/6 = ac/3

bc/2 = ac/3

bc = 2ac/3

ab + ac + bc = 54

ac/3 + ac + 2ac/3 = 54

ac/3 + 3ac/3 + 2ac/3 = 54

6ac/3 = 54

2ac = 54

ac = 54 : 2 = 27

ab = 27/3 =9

bc = 2*27/3 = 18

Answer 2

P= AB+BC+AC

P=54

$\frac{AB}{2}= \frac{AC}{6} =>AB=\frac{2AC}{6}=>AB=\frac{AC}{3}$

$\frac{BC}{2}= \frac{AC}{3} =>BC=\frac{2AC}{3}$

AB+BC+AC=54

$\frac{AC}{3} +\frac{2AC}{3} +AC=54\\\\\frac{AC}{3}+\frac{2AC}{3} +\frac{3AC}{3}=54\\\\\frac{6AC}{3}=54\\\\2AC=54\\\\AC=\frac{54}{2} \\\\AC=27cm$

$AB=\frac{AC}{3}\\\\AB=\frac{27}{3} \\\\AB=9cm$

$BC=\frac{2AC}{3} \\\\BC=\frac{2*27}{3} \\\\BC=2*9\\\\BC=18cm$