Question

permutari de 5 +aranjamente de 3 luate cate 2

Answer 1

5! + 3!/1! =1*2*3*4*5 + 1*2*3 / 1 = 120+6=126.

Answer 2

P5=5!=120
$A_{3}^{2} = \frac{3!}{(3-2)!} = \frac{1*2*3}{1} =6$
120+6=126