Question

Piramida patrulatera regulata ABCD cu AB = 6 radical din 2 si inaltimea VO = 6. Aria laterala este egal cu ...?

Answer 1

Fie M mijlocul lat.BC⇒OM-apotema bazei=3√2
                                  ⇒VM-apotema piramidei
In ΔVOM-dreptunghic⇒(teorema lui Pitagora):VM^2=OM^2+VO^2
                                                                          VM^2=18+36
                                                                            VM=3√6
Aria laterala=(P bazei ×ap):2
                    = (24√2×3√6):2
                    =72√3
Sper ca te-am ajutat! ^..^