Question

Pls dau coroana ex 8 si 11

Answer 1

8)

xA = -rad(2) + 1

xB = rad(2) + 1

L = xB - xA = rad(2) + 1 - (-rad(2) + 1) = 2 * rad(2)

L = 2 * rad(2)

11) A(rad(2)), B(rad(3)), C(rad(8) = 2 rad(2)), D(2 rad(3))

AB = xB - xA = rad(3) - rad(2)

BC = xC - xB = rad(8) - rad(3) = 2 rad(2) - rad(3)

CD = xD - xC = 2 rad(3) - 2 rad(2) = 2(rad(3) - rad(2))

AB + BC + CD = xD - xA = 2 rad(3) - rad(2) = 2*1.73-1.41 = 3.46-1.41 = 2.05 > 2

Deci: AB + BC + CD = 2.05 > 2