Question

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Answer 1

Explicație pas cu pas:

Aflăm ipotenuza BC cu teorema lui Pitagora

BC^=AB^+AC^

BC^=6^+8^

BC^=36+64

BC^=100

BC=radical din 100

BC=10

sin u =AC/BC=6/10=3/5

sin v =AB/BC= 8/10=4/5

cos u= AB/ BC=8/10=4/5

cos v=AC/BC=6/10=3/5

tg u=AC/AB=6/8=3/4

tg v=AB/AC=8/6=4/3

ctg u=AB/AC=8/6=4/3

ctg v= AC/AB=6/8=3/4