Question

Poftim ex 6
Sper sa vezi

Answer 1

Sper ca te-am ajutat:))

Answer 2

6) a) 5/12 :(1/3–3/4)–1 intreg 2/3*1 intreg 1/5
=5/12:(4/12–9/12)–5/3*6/5
=5/12:(–5/12)–30/15
=–1–2
=–3
b) √255/16+(3√5/5–3√5/10)*√5/3
=15/4+(6√5/10–3√5/10)*√5/3
=15/4+3√5/10*√5/3
=15/4+√5/5*√5/3
=15/4+5/10
=15/4+1/2
=(15+2)/4
=17/4
c) √50+√54×(3/√2–5/√27)–√108 =5√2+3√6(3√2/2–5√3/9)–6√3 =5√2+3√6×3√2/2–3√6×5√3/9–6√3 =5√2+9√12/2–5√18/3–6√3 =5√2+9√3–5√2–6√3 =3√3