Question

Prin nitrarea a 47 kg de fenol se obtin 91,6 kg produs de reactie care contine 31,44% C. Care este randamentul reactiei de nitrare?

Answer 1

C6H6O + nHNO3 -> C6H6-nO(NO2)n + nH2O
M.................100%
72.............31,44%
M=7200/31,44=229kg/kmol
M=72+6-n+16+(14+32)*n=45n+94=229
45n=135 => n=3 => trinitrare
94kg...............................229kg
C6H6O + 3HNO3 -> C6H3N3O7 + 3H2O
47kg...............................x=?
x=47*229/94=114,5kg trinitrofenol
114,5kg....................100% (randament)
91,6kg..........................y%
y=91,6*100/114,5=80%