Question

Problema 26 dau coroana

Answer 1

n total parti greutate = 42

42 p.g.....1p H.....7p N....16p O......18p C
100p.g....x..........y...........z................w

x = 2,38% H
y = 16,66% N
z = 38,095% O
w = 42,857% C

H : 2,38/1 = 2,38 : 1,19 => 2 atomi H
N : 16,66/14 = 1,19 : |1,19 => 1 atom N
O : 38,095/16 = 2,38 | :1,19 => 2 atomi O
C : 42,857/12 = 3,571 |:1,19 => 3 atomi C

F. B => (C3H2NO2)n

F.M => (C3H2NO2)n = 168 <=> 84n = 168 => n = 2 ==> C6H4N2O4

Cred ca sunt si alte metode de rezolvare, dar eu am ales-o pe asta.. :)