Question

Problema 339, raspunsul corect: A

Answer 1

CxH(2x+2)O + 3x/2 O2 ⇒ xCO2 + (x+1)H2O 
C(x+1)H(2x+4)O + (3x+ 3)/2 O2 ⇒ (x+1)CO2 + (x+2)H2O 
(3x + 3x + 3)/2 = 100,8/22,4 = 4,5       6x = 6x = 1      (CH3-OH si CH3-CH2-OH)
n1CO2 = x·n1 = n1 
n2CO2 = (x+1)·n2 = 2n2        2n2 = 4n1      n2 = 2n1
n1 moli     CH4O + 3/2 O2 ⇒ CO2 + 2H2O 
n2 moli     C2H6O + 3O2 ⇒2CO2 + 3H2O
1,5n1 + 3n2 = 84/22,4 = 3,75 
1,5n1 + 6n1 = 3,75   n1 = 0,5     n2 = 1 
n1/n2 = 0,5/1 = 1/2    (A)