Question

problema 4 .
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Answer 1

Răspuns:

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Answer 2

Explicație pas cu pas:

$|2x + 1| \leqslant 5$

$- 5 \leqslant 2x + 1 \leqslant 5 \ \ \Big| - 1$

$- 6 \leqslant 2x \leqslant 4 \ \ \Big| : 2$

$- 3 \leqslant x \leqslant 2$

$\implies A = \Big[-3 ; 2\Big]$

$- 3 < \dfrac{x + 1}{2} \leqslant 1 \ \ \Big| \cdot 2$

$- 6 < x + 1 \leqslant 2 \ \ \Big| - 1$

$- 7 < x \leqslant 1$

$\implies B = \Big(-7 ; 1\Big]$

---- (-7 ---- [-3 ------ 1] ----- 2] ----

.$A \cup B = \Big(-7 ; 2\Big]$

$A \cap B = \Big[-3 ; 1\Big]$

$A - B = \Big(1 ; 2\Big]$

$B - A = \Big(-7 ; - 3\Big)$