Question

Problema 4 varog mult......
URGENT!

Answer 1

a)∡AFE≡∡BFC (ipoteza)⇒∡AEF≡∡FCB (la unghiurii congruente corespund complemente congruente)⇒(unghi unghi)ΔAFE≈ΔBFC, cerinta
b)din a) scriem asemanare
AF/FB=AE/BC=AE/AD=1/2⇒AF=FB/2⇔FB=2AF (1)
dar AF+FB=AB=24 (2)
in locuim pe (1) in (2)
Af=2AF=24
3AF=24
AF=24:3=8, cerinta


c)AE=AF=8⇒m∡AFE=45°(3)
FB=24-8=16
BC=16⇒m∡FBC=45° (4)
din (3) si (4)⇒m∡(EFC)=180°-45°-45°=90°, cerinta
EF+FC=8√2+16√2=24√2dm≈33,94dm≈3,39m≈3,4m