Question

Problema 5 va rog! Mulțumesc anticipat!

Answer 1

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Answer 2

Aplicam proportii derivate.

a) Din $\frac{a}{b}=\frac{3}{d}$ ⇒$\frac{4a+2b}{3a+b}=\frac{4*3+2*2}{3*3+2}=\frac{16}{11}$

b) $\frac{a^{2}}{b^{2}}=\frac{9}{4}$

atunci $\frac{a^{2}+2b^{2}}{2a^{2}+b^{2}}=\frac{9+2*4}{2*9+4}=\frac{17}{22}$

c) $\frac{a^{2}-b^{2}}{6ab}=\frac{9-4}{6*3*2}=\frac{5}{36}$