Question

Problema din imagine, vă rog !

Answer 1

$\it 2-\dfrac{1}{2} +\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{12} =x\cdot\Big(1-\dfrac{1}{2}-\dfrac{1}{3}+ \dfrac{1}{4}\Big)\\\\\\\dfrac{24-6+4-3+1}{12}=x\cdot\Big(\dfrac{12-6-4+3}{12}\Big)\\\\\\\dfrac{\not20}{\not12}=x\cdot\Big(\dfrac{5}{12}\Big)\\\\\\\dfrac{5}{3}=\dfrac{5x}{12}\Rightarrow3\cdot5x=5\cdot12\:\:\:|:15\Rightarrow\boxed{\it x = 4}$

Răspuns:  x = 4