Question

problemele 15 si 16 din imagine va rog foarte mult

Answer 1

15)
c₁=md₁*100/ms₁
ms₁=2000+150=2150 g
c1=150*100/2150=6.97%

c₂=md₂*100/ms₂
ms₂=4000+500=4500 g
c₂=500*100/4500=11.11%
a)fals, solutia de socata este mai concentrata decat cea de limonada (11.11>6.97)
b)fals, c₁≠c₂
c)fals, c₁ si c₂ <100
d) c₂/c₁=11.11/6.97=1.59, adevarat. Socata este mai dulce decat limonada de 1.59 ori.
e)fals, limonada nu este mai dulce decat socata deoarece c1<c2

16)
c₁=28%
ρ₁=1.310 g/cm³
c₂=56%
ρ₂=1.601 g/cm³
c₃=40%
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V₁/V₂=?
ρ₃=?
-----------
c₁=md₁*100/ms₁
c₂=md₂*100/ms₂
ρ₁=ms₁/V₁
ρ₂=ms₂/V₂
ρ₃=(ms₁+ms₂)/(V₁+V₂)
c₃=(md₁+md₂)*100/(ms₁+ms₂)
ms₁+ms₂=(md₁+md₂)*100/c₃=(md₁+md₂)*100/40
40ms₁+40ms₂=100md₁+100md₂
md₁=c₁ms₁/100=28ms₁/100
md₂=c₂ms₂/100=56ms₂/100
40ms₁+40ms₂=28ms₁+56ms₂
12ms₁=16ms₂
ms₁=16ms₂/12=4ms₂/3
ρ₂/ρ₁=ms₂*V₁/V₂*ms₁=(V₁/V₂)*(3ms₂/4ms₂)
ρ₂/ρ₁=(V₁/V₂)*3/4
1.601/1.310=(V₁/V₂)*3/4
V₁/V₂=6.404/3.93

ms₁=ρ₁* V₁ = 1.310*6.404=8.38 g masa solutie
ms₂=ρ₂ * V₂ = 1.601*3.93=6.29 g masa solutie
ρ₃=(ms₁+ms₂)/(V₁+V₂)=(8.38+6.29)/(6.404+3.93)=1.419 g/cm³