Question

punctele incercuite ...va rog dau 40 p​

Answer 1

Răspuns:

Explicație pas cu pas:

g) (1/81)ˣ·√3 > 1  <=>

(1/3⁴)ˣ· 3¹⁽²  > 1  <=>

3⁻⁴ˣ⁺¹⁽²  > 3⁰  =>

-4x + 1/2  > 0  =>

-4x > -1/2  => x > (-1/2)/(-4) =>

x > 1/8  => x ∈ (1/8 , +∞)

h) (1/⁵√0,5 )ˣ < 1/4  <=>

1/ (0,5)ˣ⁽⁵ < 1/4  <=>

1/(1/2)ˣ⁽⁵ < 1/2²  <=>

2ˣ⁽⁵ < 2⁻²  =>

x/5 < -2  =>

x < -10 => x ∈ (-∞ , -10)

i) 32(∛2)ˣ > 0,25  <=>

2⁵· 2ˣ⁽³  > 25/100  <=>

2⁵⁺ˣ⁽³ > 1/4  <=>

2⁵⁺ˣ⁽³ > 1/2² <=>

2⁵⁺ˣ⁽³ > 2⁻²  =>

5+x/3 > -2  =>

x/3 > -7 =>

x > -21  => x ∈ (-21 , +∞)