Question

Punctul d)!Va rog.
Ofer 50 de puncte!!

Answer 1

modulul se anileaz pt 2x+3=0 deci x=-3/2

Discutie:

a) pt x>-3/2

3(2x+3+4x-9)+5=4x+36+8x-16

3(6x-6)+5=12x+20

18x-18+5=12x+20

6x-13=20

6x=33 |  împartim prin 3

2x=11

x=11/2>0>-3/2 deci solutia convine

pt x<-3/2

3(-2x-3+4x-9)+5=12x+20

3(2x-12)=12x+20

4x-36=12x+20 impartim toat relatia prin 4

x-9=3x+5

-9-5=3x-x

-14=2x

2x=-14

x=-7<-3/2 solutia convine

c) pt x=-3/2

4x-9+5=12x-20

4x-4=12x-20

x-1=3x-5

4=2x

x=2 , contradictie, -3/2 nu e solutie

x∈{-7;11/2}