Question

Punctul d va rog punctaj maxim

Answer 1

{ [(12²+5²):13]²-2⁷-2⁰}:2³={ [(144+25):13]²-128-1}:2³={ [169:13]²-128-1}:2³=
(13²-128-1):2³=(169-128-1):8=40:8=5


x:(2³)⁰=1
x:8⁰=1
X:1=1
x=1

Answer 2

$\left \{ [( 12^{2} + 5^{2} ):13]^{2} - 2^{7} - 2^{0}} \right \}:2^{3}$
$\left \{ [(144+25):13]^{2} - 2^{7} - 2^{0}} \right \} :2^{3}$
$[(169:13)^{2} - 2^{7} - 2^{0}] : 2^{3}$
$(13^{2} - 2^{7} - 2^{0}}) : 2^{3}$
$(169 - 128 - 1) : 8$
$(41-1):8$
$40:8$
$5$