Question

Putin ajutor? 10 sau 11

Answer 1

Răspuns:

Explicație pas cu pas:

$10. \texttt{Folosim formula }log_ab=\dfrac{\ln a}{\ln b}\\p=\log_24\cdot\log_48\cdot\log_816\cdot\ldots\cdot\log_{2^n}2^{n+1}\\\\ p=\dfrac{\ln 4}{\ln 2}\cdot \dfrac{\ln 8}{\ln 4}\cdot\ldots \cdot \dfrac{\ln 2^{n+1}}{\ln 2^{n}}\\ p=\dfrac{\ln2^{n+1}}{\ln 2}=log_22^{n+1}=n+1\\{[p]}=2019\\{[n+1]}=2019\\{[n]}+1=2019\\{[n]}=2018\\\texttt{Cum }n\in\mathbb{N*}\texttt{ rezulta ca }n=2018$

Answer 2

11 , vezi poza atasata!!!!!