Question

Q= log in baza 3 din 35- log in baza 3 din 10 +log  in baza 3 din 12-log in baza 3 din 14
Q=?

Answer 1

= $log_{3} ( \frac{35}{10}* \frac{12}{14} )= log_{3} ( \frac{7}{2}* \frac{12}{14} )= log_{3} 3 =1$