Question

rad x^2+x+2=x^2+x
rezolvati in multimea numerelor reale ecuatia de mai sus

Answer 1

Explicație pas cu pas:

$\sqrt{x^{2} +x+2} =x^{2} +x\\x^{2} +x+2=(x^{2}+x}){^{2} \\\\x^{2} +x+2=x^{4} +2x^{3} +x^{2} \\x^2+x+2-x^4-2x^3-x^2=0\\x^4+2x^3-x-2=0\\x^3(x+2)-(x+2)=0\\(x^3-1)(x+2)=0\\\\\(x-1)*(x^2+x+1)*(x+2)=0\\x=1\\x=-2\\Bafta!$