Question

|rad12-2|+|1-rad2|+|2rad3-5|+|4+rad12|

Answer 1

$| \sqrt{12} - 2 | + |1 - \sqrt{2} | + |2 \sqrt{3} - 5| + |4 + \sqrt{12} | = |2 \sqrt{3} - 2| + \sqrt{2} - 1 + 5 - 2 \sqrt{3} + |4 + 2 \sqrt{3} | = 2 \sqrt{3} - 2 + \sqrt{2} - 1 + 5 - 2 \sqrt{3} + 4 + 2 \sqrt{3} = 6 + \sqrt{2} + 2 \sqrt{3}$