Question

(Radical din 2 -1) ( radical din 2 -5)

Answer 1

[tex](\sqrt2-1)(\sqrt2-5)=\sqrt2^2-\sqrt2-5\sqrt2+5=2-6\sqrt2+5=\\ =7-6\sqrt2\\ \frac{\sqrt2-1}{\sqrt2-5}=\frac{(\sqrt2-1)(\sqrt2+5)}{(\sqrt2-5)(\sqrt2+5)}=\\ \frac{2+4\sqrt2-5}{2-25}=\frac{3-4\sqrt2}{23}[/tex]

Answer 2

$( \sqrt{2} -1)( \sqrt{2} -5)=2-5 \sqrt{2} - \sqrt{2} +5=7-6 \sqrt{2}$