Question

Radical din 27 + radical din 75 - radical din 48 = ...

Answer 1

$\sqrt{27}+\sqrt{75}-\sqrt{48}=3\sqrt{3} +5\sqrt{3}-4\sqrt{3} =8\sqrt{3}-4\sqrt{3}=4\sqrt{3}$

Answer 2

$\sqrt{27}=3 \sqrt{3}, \sqrt{75}=5 \sqrt{3}, \sqrt{48}=4 \sqrt{3}$
$3 \sqrt{3}+5 \sqrt{3}-4 \sqrt{3}=8 \sqrt{3} -4 \sqrt{3}=4 \sqrt{3}$