Question

radical din 3^2 + 3^4 supra 2^4​

Answer 1

$\it \sqrt{3^2}+\dfrac{3^4}{2^4}=9+\dfrac{81}{16}=\dfrac{9\cdot16+81}{16}=\dfrac{225}{16}=14,0625$

$\it \sqrt{3^2}+\dfrac{3^4}{2^4}=9+\Big(\dfrac{3}{2}\Big)^4=9+(1,5)^4=9+5,0625=14,0625$