Question

radical din 5 • minus radical din 2

Answer 1

$\displaystyle{ \sqrt{5} \cdot (-\sqrt{2}) = }$

$\displaystyle{ = - \sqrt{5} \cdot \sqrt{2} }$

$\displaystyle{ = -\sqrt{5 \cdot 2} }$

$\boxed{=-\sqrt{10}}$