Question

Radical din 50-5radicaldin 8+radical din 2+radical din 128?

Answer 1

   
[tex] \sqrt{50}-5 \sqrt{8}+ \sqrt{2}+ \sqrt{128}= \\ =\sqrt{25 \times 2}-5 \sqrt{4 \times 2}+ \sqrt{2}+ \sqrt{64 \times 2}= \\ =5\sqrt{2}-5 \times 2 \sqrt{2}+ \sqrt{2}+ 8\sqrt{2}= 5\sqrt{2}-10\sqrt{2}+ \sqrt{2}+ 8\sqrt{2}=\boxed{4\sqrt{2}}[/tex]

Answer 2

rad50-5rad8+rad2+rad128=5rad2-10rad2+rad2+8rad2=4rad2