Question

Radical din x patrat minus 4 + radical din x-2 =0

Answer 1

√x^2-√x-2=0
√x^2-√x=0+2
√x^2-√x=2
√x=2
x=2^2
x=4

Answer 2

$\sqrt{ x^{2}-4 }+ \sqrt{ x-2} =0 [/tex [tex] \sqrt{ x^{2}-4 }= -\sqrt{x-2}$
$x^{2} -4=x-2$
$x^{2} -x-2=0$
Δ=9
$x_{1} =-1$∉DVA
$x_{2}=2$
S={2}