Question

Radical mare din 7 - 4 radical din 3

Answer 1

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Answer 2

[tex]\it \sqrt{7-4\sqrt3} =\sqrt{4+3-4\sqrt3} =\sqrt{2^2-4\sqrt3+(\sqrt3)^2} = [/tex]

$\it =\sqrt{(2-\sqrt3)^2} =|2-\sqrt3 | =2 -\sqrt3\ .$