Question

radical125+radical45-8radical5​

Answer 1

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Answer 2

$\sqrt{125} = \sqrt{5 \times {5}^{2} } = 5 \sqrt{5} \\ \sqrt{45} = \sqrt{5 \times {3}^{2} } = 3 \sqrt{5} \\ \sqrt{125} + \sqrt{45} - 8 \sqrt{5} = 5 \sqrt{5} + 3 \sqrt{5} - 8 \sqrt{5} = 8 \sqrt{5} - 8 \sqrt{5} = 0$