Question

raportul a doua numere este 1/4 si suma lor tot atat
media aritmetica si cea geometrics a nr este?

Answer 1

a/b=1/4 => b=4a
a+b=1/4
a+4a=1/4
5a=1/4 => a=1/20
b=1/5
(1/20 + 1/5)/2=(1+4)/40=5/40=1/8
rad(1/20 • 1/5)=rad(1/100)=1/10

Answer 2

$\frac{x}{y} = \frac{1}{4} =\ \textgreater \ y=4x\\\\ x+y= \frac{1}{4} \ \textless \ =\ \textgreater \ x+4x= \frac{1}{4} =\ \textgreater \ 5x= \frac{1}{4} =\ \textgreater \ x= \frac{ \frac{1}{4} }{5} \\\\ =\ \textgreater \ x= \frac{1}{4} * \frac{1}{5} =\ \textgreater \ x= \frac{1}{20} \\\\ =\ \textgreater \ y=4* \frac{1}{20} =\ \textgreater \ y= \frac{4}{20} =\ \textgreater \ y= \frac{1}{5}$

$m_a= \frac{ \frac{1}{5} + \frac{1}{20} }{2} \\\\ m_a= \frac{ \frac{4+1}{20} }{2} \\\\ m_a= \frac{ \frac{5}{20} }{2} \\\\ m_a= \frac{ \frac{1}{4} }{2} \\\\ m_a= \frac{1}{4} * \frac{1}{2} \\\\ m_a= \frac{1}{8}$

$m_g= \sqrt{ \frac{1}{5} * \frac{1}{20} } \\\\ m_g= \sqrt{ \frac{1}{100} } \\\\ m_g= \frac{1}{10}$