Question

Raportul molar solvat/solvent din 1112g de solutie acid sulfuric cu concentratia procentuala , c=35,25% este egal cu:
A) 1 : 10 B) 1 : 5 C) 2 : 3

Answer 1

Cp=md/ms*100==>md=Cp*ms/100=1112*35.25/100=391.98g=

ms=md+mH2O(solvent)==>mH2O=ms-md=1112-391.98=720g

n=m/M=400/98=391.98/98=4 moli H2SO4
n=m/M=720/18=40 moli H2O

nH2SO4/nH2O=4/40=1/10 sau 1:10 ==> Raspuns corect A)

MH2SO4=98g/mol
MH2O=18g/mol