Question

Rationalizati: 1/(√8+√12-√6-√3-√2)

Answer 1

 1/(2√2+2√3-√6-√3-√2) =
= 1/(√2+√3-√6) =
= (√2+√3+√6) /(√2+√3-√6) (√2+√3+√6) =
= (√2+√3+√6) /[(√2+√3)²-(√6)²] =
= (√2+√3+√6) /(2+3+2√6-6) =
= (√2+√3+√6) /(2√6-1) =
= (√2+√3+√6) (2√6+1)/(2√6-1)(2√6+1) =
= (2√12+2√18+12+√2+√3+√6)/(24-1)=
= (4√3+6√2+12+√2+√3+√6)/23=
= (5√3+7√2+√6+12)/23