Question

rationalizati numitorii fiecarui raport
$\frac{1}{ \sqrt{3 } + \sqrt{2} }$

Answer 1

$\frac{1}{\sqrt{3}+\sqrt{2}} = \frac{1\cdot \left(\sqrt{3}-\sqrt{2}\right)}{\left(\sqrt{3}+\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)} = \frac{\sqrt{3}-\sqrt{2}}{1} = \sqrt{3}-\sqrt{2}$