Question

Rationalizati numitorul...

5 supra 3√10
..........
8 supra √6-√2
...................
2 supra 2√3-1
.................
2 supra √5-√3

Answer 1

5/3√10=[5/3√10]x[3√10/3√10]=15√10/90=3√10/18=√10/6

2/(√6-√2)=[2/(√6-√2)]x[(√6+√2)/(√6+√2)]=[2(√6+√2)]/(6-2)=2(√6+√2)/4=(√6+√2)/2

2/(2√3-1)=[2/(2√3-1)]x[(2√3+1)/(2√3+1)]=2(2√3+1)/(12-1)=2(2√3-1)/11

2/(√5-√3)=[2/(√5-√3)]x[(√5+√3)/(√5+√3)]=2(√5+√3)/(5-3)=2(√5+√3)/2=√5+√3