Question

Rationalizati numitorul: $\frac{6}{3 \sqrt{2}-2 \sqrt{3} }$

Answer 1

$\frac{6}{3 \sqrt{2}-2 \sqrt{3} } = \frac{6(3 \sqrt{2} +2 \sqrt{3} )}{18-12} = \frac{6(3 \sqrt{2} +2 \sqrt{3} )}{6} =3 \sqrt{2} +2 \sqrt{3}$

Answer 2

= 6 · ( 3√2 + 2√3 )   / ( 3√2 -2√3) · ( 3√2 + 2√3) = 6 ·( 3√2 + 2√3) /6 = 
                                               = 3√2 + 2√3

 ( 3√2 - 2√3) · ( 3√2 + 2√3) = (3√2) ² - ( 2√3)² = 18 - 12 = 6