Question

Reazolvati ecuatiile:
a) x-(7^2-11•4)=29•8-2^5
b) 6×x:15+7^2×5+17×3-27​

Answer 1

Răspuns:

a)

x - (7^2 - 11 • 4) = 29 • 8 - 2^5

x - (49 - 44) = 232 - 32

x - 5 = 200

x = 200 + 5

x = 205

b)

6 • x : 15 + 7^2 • 5 = 15^2 + 17 • 3 - 27

6 • x : 15 + 49 • 5 = 225 + 51 - 27

6 • x : 15 + 245 = 249

6 • x : 15 = 249 - 245

6 • x : 15 = 4  

6 • x = 4 • 15

6 • x = 60

x = 60 : 6

x = 10

Answer 2

$\purple{ \bf a)\:\: x= 205}$

$\red{\bf b)\:\: x = 10}$

Explicație pas cu pas:

Bună !

$\bf \: a) \: x - \big( {7}^{2} - 11 \cdot4 \big) = 29 \cdot 8 - {2}^{5}$

$\bf \: x - \big( 49 - 44 \big) = 29 \cdot 8 - {2}^{5}$

$\bf \: x - 5 = 29 \cdot 8 - {2}^{5}$

$\bf \: x= 29 \cdot 8 - {2}^{5} + 5$

$\bf \: x= 232 - 32 + 5$

$\purple{ \underline{\bf \: x= 205}}$

$\bf$

$\bf b) \: \: 6 \cdot x : 15 + {7}^{2} \cdot 5 = {15}^{2} + 17 \cdot 3 - 27$

$\bf 6 \cdot x : 15 + 49 \cdot 5 = {15}^{2} + 17 \cdot 3 - 27$

$\bf 6 \cdot x : 15 + 245 = {15}^{2} + 17 \cdot 3 - 27$

$\bf 6 \cdot x :15 ={15}^{2} + 17 \cdot 3 - 27 - 245$

$\bf 6 \cdot x :15 =225+ 51- 27 - 245$

$\bf 6 \cdot x : 15 =276- 27 - 245$

$\bf 6 \cdot x : 15 =4 \: \: \: \: \bigg| \cdot15$

$\bf 6 \cdot x = 60 \: \: \: \bigg|: 6$

$\red{ \underline{\bf x = 10}}$

Baftă multă !