Question

Redu termeni asemena in urmatoarele cazuri :7a+3b-5b-8a =
10x²+5x-1-18x²-3x+8=
2x²+y²-4xy-4y²+xy--x³y+x²y²+x³y+2xy+1-2xy=

Calculati:
(x+2)(x+3)=
(x-1)(x-4)=
(x+5)(x²+xy+y²​

Answer 1

Răspuns:

7a+3b-5b-8a=-a-2b

10x²-18x²+5x-3x-1+8=-8x²+2x+7

2x²-3y²-5xy+x²y²+1

(x+2)(x+3)=x²+5x+6

(x-1)(x-4)=x²-5x+4

(x+5)(x²+xy+y²)=x³+x²y+xy²+5x²+5xy+5y²