Question

Repede !!!!!
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Answer 1

$f:\mathbb{R}\rightarrow\mathbb{R} \: \: \: ,f(x)=\frac{3}{2}x+1$

$A(0,1),B(4,7)$

$a)A(0,1)\:\in\:G_{f}<=>f(0)=1$

$\frac{3}{2} \times 0 + 1 = 1$

$0 + 1 = 1$

$1 = 1 \: (A)$

$B(4,7)\:\in\:G_{f}<=>f(4)=7$

$\frac{3}{2} \times 4 + 1 = 7$

$3 \times 2 + 1 = 7$

$6 + 1 = 7$

$7 = 7 \: (A)$

$c)AB=\sqrt{{(x_{B}-x_{A})}^{2}+{(y_{B}-y_{A})}^{2}}$

$AB = \sqrt{ {(4 - 0)}^{2} + {(7 - 1)}^{2} }$

$AB = \sqrt{ {4}^{2} + {6}^{2} }$

$AB = \sqrt{16 + 36}$

$AB = \sqrt{52}$

$AB = 2 \sqrt{13}$