Question

REPEDE DAU COROANA
SI AUNT AI 100 DE PUNCTE VA ROG REPEDE
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Answer 1

a) -3*[11-3*(-5+6)] =

-3*[11-3*1] =

-3*[11-3] = -3*8 = -24

b) -2*[-5+(-2)*(7-12)]+21 =

-2*[-5+(-2)*(-5)]+21 =

-2*[-5+10]+21 =

-2*5+21 = -10+21 = 11

c) 19+45: [-11+2¹⁹:2¹⁸] +2*9 =

19+45: [-11+2]+18 =

19+45:(-9)+18 =

19-5+18 = 32

d) 23-4*[27:(25-16)+1] =

23-4*[27:9+1] =

23-4*[3+1]=

23-4*4 = 23-16 = 7

e) -10+7*12:42+8 =

-10+84:42+8 =

-10+2+8= -8+8=0

f) 24+5*(2³ -6)+9 =

24+5*(8-6)+9 =

24+5*2+9 =

24+10+9 = 43

Answer 2

Răspuns:

$\bf \purple{a)~ -24}$

$\bf \pink{b)~~~~~ 11}$

$\bf \blue{c)~~~~~ 32}$

$\bf \red{d)~~~~~~ 7}$

$\bf \orange{e)~~~~~~ 0}$

$\bf \green{f)~~~~~ 43}$

Explicație pas cu pas:

Bună !

$\bf a)~~ -3\cdot \big[11-3\cdot \big(-5+2\cdot 3 \big)\big] =$

$\bf -3\cdot \big[11-3\cdot \big(-5+6 \big)\big] =$

$\bf -3\cdot \big(11-3\cdot 1\big) =$

$\bf -3\cdot \big(11-3\big) =$

$\bf -3\cdot 8 = \purple{\underline{-24~}}$

$\it~~$

$\bf b)~~ -2\cdot \big[-5+\big(-2\big)\cdot\big(7-4\cdot3\big)\big]-7\cdot \big(-3\big)=$

$\bf -2\cdot \big[-5+\big(-2\big)\cdot\big(7-12\big)\big]-7\cdot \big(-3\big) =$

$\bf -2\cdot \big[-5+\big(-2\big)\cdot\big(-5\big)\big]+7\cdot3 =$

$\bf -2\cdot \big(-5+10\big)+21 =$

$\bf -2\cdot 5 +21 =$

$\bf -10 +21 =\pink{\underline{~11~}}$

$\it~~$

$\bf c)~~ 19+45: \Big[-11+2^{19}:\big(-2\big)^{18}\Big] -\big(-2\big)\cdot 9=$

$\bf 19+45: \Big(-11+2^{19}:2^{18}\Big) +2\cdot 9=$

$\bf 19+45: \Big(-11+2^{19-18}\Big) +18=$

$\bf 19+45: \Big(-11+2^{1}\Big) +18=$

$\bf 19+45: \big(-9\big) +18=$

$\bf 19-45: 9 +18=$

$\bf 19-5 +18=$

$\bf 14 +18=\blue{\underline{~32~}}$

$\it~~$

$\bf d)~~ 23-4\cdot \Big[3^{3}:\big(5^{2} -4^{2} \big)+1\Big] =$

$\bf 23-4\cdot \Big[3^{3}:\big(25 -16\big)+1\Big] =$

$\bf 23-4\cdot \big(27:9+1\big) =$

$\bf 23-4\cdot \big(3+1\big) =$

$\bf 23-4\cdot 4=$

$\bf 23-16=\red{\underline{~7~}}$

$\it~~$

$\bf e)~~ -10+7\cdot \big(21-9\big):42+2^{3} =$

$\bf -10+7\cdot 12:42+2^{3} =$

$\bf -10+84:42+2^{3} =$

$\bf -10+2+2^{3} =$

$\bf -10+2+8 =$

$\bf -10+10 =\orange{\underline{~0~}}$

$\it~~$

$\bf f)~~ 24-\big(-5\big)\cdot \Big(2^{20}:2^{17} -3\cdot2\Big)+3^{2} =$

$\bf 24+5\cdot \Big(2^{20-17} -3\cdot2\Big)+3^{2} =$

$\bf 24+5\cdot \Big(2^{3} -6\Big)+3^{2} =$

$\bf 24+5\cdot \big(8 -6\big)+9 =$

$\bf 24+5\cdot 2+9 =$

$\bf 24+10+9 = \green{\underline{~43~}}$

$\red{\star~~\underline{\underline{\text{\bf Formule pentru puteri:}}}}$

$\red{\Large \bf a^{0} = 1}$

$\red{\Large \bf \big(a^{n}\big)^{m} = a^{n \cdot m}}$

$\red{\Large \bf a^{n}\cdot a^{m} =a^{n+m}}$

$\red{\Large \bf a^{n}: a^{m} =a^{n-m}}$

P.S. Dacă ești pe telefon te rog să glisezi spre stânga pentru a vedea întreaga rezolvare.

Baftă multă !