Question

Repede va rog! Dau coroana

Answer 1

a)[tex] \sqrt{2} * ( \frac{4}{3 \sqrt{2} } + \sqrt{ \frac{2}{9} } ) + \sqrt{3} * ( \sqrt{ \frac{3}{9} } + \frac{2}{ \sqrt{3} } ) = [tex] \frac{4}{3} + \sqrt{3} * \frac{3}{ \sqrt{3} } = \frac{4}{3} + 3= \frac{13}{3} [/tex]

[tex]\sqrt{5} * ( \frac{5}{3 \sqrt{5} } + \sqrt{ \frac{5}{9} } + \frac{ 2 \sqrt{5} }{6} ) - \sqrt{6} * ( \sqrt{\frac{6}{9} } + \frac{ 2 \sqrt{2} }{ \sqrt{3} })= \frac{5}{3} + \frac{5}{3} + \frac{10}{6} - \s 2 + 4= [/tex]$\frac{30}{6} +2=7$

c) ($\frac{14}{3 \sqrt{7} } - \frac{15}{5 \sqrt{7} } + \frac{6 \sqrt{7} }{4} - \frac{2}{3 \sqrt{7} } + \frac{ \sqrt{7} }{2} - \frac{14 }{2 \sqrt{7} } =$$[tex] \frac{14}{3 \sqrt{7} } - \frac{3}{ \sqrt{7} } + \frac{3 \sqrt{7} }{2} - \frac{2}{3 \sqrt{7} } + \frac{ \sqrt{7} }{2} - \frac{7}{ \sqrt{7} }$= [tex] \frac{4}{ \sqrt{7} } - \frac{4}{ \sqrt{7} } +2 \sqrt{7} =2 \sqrt{7} [/tex]

d)[tex] \frac{12 \sqrt{5} }{7 \sqrt{5} } *( \frac{3}{6 \sqrt{6} } + \sqrt{ \frac{15}{90} } - \frac{5}{ \sqrt{6} } = \frac{12}{7} * ( \frac{1}{2 \sqrt{6} } + \frac{1}{ \sqrt{6} } - \frac{5}{ \sqrt{6} }= \frac{12}{7} * \frac{-7}{2 \sqrt{6} }= \frac{-6}{ \sqrt{6} } [/tex]